View Full Version : Math Help
AlexShymkiw
28th March 2007, 14:34
Okay all you math whizs out there, I need your help. I'm upgrading Math 11 for post-secondary and I haven't done the course for about two years. My tutor is away at the moment. I'm a little bit rusty so I need your help in solving this review question to prepare for the Chapter test.
-5/3X + 7/3 = -5
The answer is 22/5
Can anyone outline for me what steps I need to take to identify what X is?
dan_the_man
29th March 2007, 08:11
The answer is wrong.
It's 5 over 22.
-5/3X + 7/3 = -5
-5(3) + 7(3X) = -5(3)(3X)
-15 + 21X = -45X
-15 = -66X
15=66X
X=15/66
X= 5/22
There you go.
chippie
29th March 2007, 09:15
The answer is wrong.
It's 5 over 22.
-5/3X + 7/3 = -5
-5(3) + 7(3X) = -5(3)(3X)
-15 + 21X = -45X
-15 = -66X
15=66X
X=15/66
X= 5/22
There you go.
The answer is indeed 22 over 5 or 22/5.
-5/3X + 7/3 = -5
(-5/3X + 7/3 = -5) ÷ 3 <-- take the whole equation and divide it by 3.
(-5/3X x 3/1) + (7/3 x 3/1) = (-5 x 3/1)
-5X + 7 = -15
-5X = -15 - 7
-5X = -22
X = -22 ÷ -5
X = 22/5 aka 22 over 5.
To check your answer:
-5/3X + 7/3 = -5
(-5/3 x 22/5) + 7/3 = -5
-22/3 + 7/3 = -5
-15/3 = -5
-5 = -5 <-- It balanced and work!!!
dan_the_man
29th March 2007, 09:26
The answer is indeed 22 over 5 or 22/5.
-5/3X + 7/3 = -5
(-5/3X + 7/3 = -5) ÷ 3 <-- take the whole equation and divide it by 3.
(-5/3X x 3/1) + (7/3 x 3/1) = (-5 x 3/1)
-5X + 7 = -15
-5X = -15 - 7
-5X = -22
X = -22 ÷ -5
X = 22/5 aka 22 over 5.
To check your answer:
-5/3X + 7/3 = -5
(-5/3 x 22/5) + 7/3 = -5
-22/3 + 7/3 = -5
-15/3 = -5
-5 = -5 <-- It balanced and work!!!
:rofl: I truly hope you're right (Math isn't my métier). Then I can go up to the Math teacher and tell him he's wrong (yet holds a baccalaureate in Economics, Math, etc.). He told me the answer was 5 over 22. Unbelievable!:lol:
AlexShymkiw
29th March 2007, 19:22
:dance: Thanks, it took a little bit longer than expected to get back into the swing of things.
Mr G
29th March 2007, 19:30
:rofl: I truly hope you're right (Math isn't my métier). Then I can go up to the Math teacher and tell him he's wrong (yet holds a baccalaureate in Economics, Math, etc.). He told me the answer was 5 over 22. Unbelievable!:lol:
Yeah the answer of 5/22 is right. In the solution you presented, the error was make in the first step of the solution.
Juice
29th March 2007, 19:42
The answer is indeed 22 over 5 or 22/5.
-5/3X + 7/3 = -5
(-5/3X + 7/3 = -5) ÷ 3 <-- take the whole equation and divide it by 3.
(-5/3X x 3/1) + (7/3 x 3/1) = (-5 x 3/1)
-5X + 7 = -15
-5X = -15 - 7
-5X = -22
X = -22 ÷ -5
X = 22/5 aka 22 over 5.
To check your answer:
-5/3X + 7/3 = -5
(-5/3 x 22/5) + 7/3 = -5
-22/3 + 7/3 = -5
-15/3 = -5
-5 = -5 <-- It balanced and work!!!
Yeah, it is indeed 5/22. Your mistake happened where I have noted by bolding and underlining. When you multiply -5/3x by 3, you get -5/x, not -5x.
So your solution should look like this:
a) -5/3x + 7/3 = -5
b) 3(-5/3x) + 3(7/3) = 3(-5)
c) -5/x + 7 = -15
d)-5/x = -15 - 7
e) x(-5/x) = x(-22)
f) -5 = -22x
g) -5/-22 = -22x/-22
Therefore:
h) x = 5/22
JB
N. McKay
29th March 2007, 19:49
I make it 5/22 as well:
-5/(3x) + 7/3 = -5
-5/(3x) = -5/1 - 7/3
-5/(3x) = -15/3 - 7/3
-5/(3x) = -22/3
5/(3x) = 22/3
5 * 3 = 22 * (3x)
15 = 66x
15/66 = x
5/22 = x
chippie
29th March 2007, 21:00
I guess it's time for me to upgrade my math as well :fist:
What I'm confuse is -5/3 of X or -5/(3X)?
I used -5/3 of X and that's how I came up with 22/5 as the answer.
Juice
29th March 2007, 21:03
I guess it's time for me to upgrade my math as well :fist:
Don't worry, it took me mulling over it for a day to finally figure it out ;)
JB
Mr G
29th March 2007, 21:13
Personally... I'm not 100% sure the question is being interpreted right. Is the 'x' associated with the numerator or the denominator. That would make the answer of 22/5 correct. Something is giving me a strong hunch that's what makes that answer the correct one.
Juice
29th March 2007, 21:27
Personally... I'm not 100% sure the question is being interpreted right. Is the 'x' associated with the numerator or the denominator. That would make the answer of 22/5 correct. Something is giving me a strong hunch that's what makes that answer the correct one.
I would imagine the 'x' is being associated with the denominator, making 5/22 the correct answer, as you can see with my solution.
JB
Mr G
29th March 2007, 21:30
I would imagine the 'x' is being associated with the denominator, making 5/22 the correct answer, as you can see with my solution.
JB
If the answer was originally quoted as being 22/5, then I can imagine that it was indeed associated with the numerator. I think that perhaps the original poster just wrote out the question incorrectly
chippie
29th March 2007, 21:31
Mr. Shymkiw can you scan the equation from your book and post it here? It's starting to bug me trying to figure this out.
Mr G
29th March 2007, 21:34
Mr. Shymkiw can you scan the equation from your book and post it here? It's starting to bug me trying to figure this out.
Yeah me too.
dan_the_man
30th March 2007, 04:29
Hmmm, somehow I knew that was the right answer (5/22).
N. McKay
30th March 2007, 11:17
As the OP has typed it the x belongs, strictly speaking, to the numerator (because you proceed left to right with multiplication and division as you meet them) so 5/3x = 1.667x, the same as 5x/3=1.667x.
My solution assumes that the x belongs to the denominator because it's a little but more intuitive for a person to have typed it that way.
It could be:
5
- x
3
which is equal to
5x
-
3
or it could be
5
-
3x.
The last of these was my assumption.
Mr G
30th March 2007, 11:34
As the OP has typed it the x belongs, strictly speaking, to the numerator (because you proceed left to right with multiplication and division as you meet them) so 5/3x = 1.667x, the same as 5x/3=1.667x.
My solution assumes that the x belongs to the denominator because it's a little but more intuitive for a person to have typed it that way.
It could be:
5
- x
3
which is equal to
5x
-
3
or it could be
5
-
3x.
If x belongs to the denominator... 5/(3x) is 1.667/x. You cannot move the x up top.
AlexShymkiw
30th March 2007, 12:34
Mr. Shymkiw can you scan the equation from your book and post it here? It's starting to bug me trying to figure this out.
You guys will have to hold out until Saturday morning, my textbook is at home. But I'll be sure to scan it then. :woot:
N. McKay
30th March 2007, 15:45
If x belongs to the denominator... 5/(3/x) is 1.667/x. You cannot move the x up top.
If x belongs to the denominator then it's 5/(3x). Where are you getting the extra / between 3 and x?
Mr G
30th March 2007, 21:31
If x belongs to the denominator then it's 5/(3x). Where are you getting the extra / between 3 and x?
Mistype on my part... I'll fix that up to avoid any further confusion in this thread.
AlexShymkiw
31st March 2007, 20:56
To clarify my original post:
http://www.cadet-world.com/cwforums/attachment.php?attachmentid=4106&d=1175402939
Juice
31st March 2007, 21:07
To clarify my original post:
http://www.cadet-world.com/cwforums/attachment.php?attachmentid=4106&d=1175402939
That makes the correct answer 22/5:
1) (-5/3)x + 7/3 = -5
2) 3[(-5/3)x] + 3(7/3) = 3(-5)
3) -5x + 7 = -15
4) -5x = -15 - 7
5) -5x/-5 = -22/-5
6) x = 22/5
JB
MThornback
1st April 2007, 21:14
I'm alergic to math...but i'm glad you got an awnser....personally...I took a look at this thread, realized my limitations and turned tail and ran :p
Conquistador
1st April 2007, 21:53
Okay all you math whizs out there, I need your help. I'm upgrading Math 11 for post-secondary and I haven't done the course for about two years. My tutor is away at the moment. I'm a little bit rusty so I need your help in solving this review question to prepare for the Chapter test.
-5/3X + 7/3 = -5
The answer is 22/5
Can anyone outline for me what steps I need to take to identify what X is?
-5/(3x) + 7/3 = -5 is equivalent to the simpler equation:
-5/x + 7 = -15 (multiply both sides by 3), or
5/x - 7 = 15 (multiply both sides by -1), which is then equivalent to
5/x = 15 + 7 = 22
Now, taking the reciprocal of both sides, we obtain the expression
x = 22/5, or 22 divided by 5.
A more fundamental way to look at the question is to consider the intersection of the functions f(x) = 5/x and the function g(x ) = 22. The function 5/x is monotonically decreasing (that is, as x gets large, f(x) gets small), and g(x ) is a constant, so there is at most one intersection.
To see this, if a function f(x ) (any function, not necessarily the one in the problem) is strictly decreasing or increasing, that is, always moving up or down in only one direction, then it can cross any single horizontal line once.
RMC 24409
1st April 2007, 22:06
There ought to be a formula out there that cancels everything established until now. At least that's not calculus...oh oh, headaches coming back:banghead:
Conquistador
2nd April 2007, 02:24
The great thing about math is that no established result can ever be overturned (unlike in any other science, where all established results to date are subject to be replaced by a better, more coherent theory), since a mathematical result cannot be 'established' until proven rigorously. For example, the Goldbach Conjecture is almost guaranteed to be true, and many famous mathematicians such as Leonhard Euler have agreed to that sentiment, yet it is still an open problem with no end in sight because no one is able to prove it rigorously.
RMC 24409
2nd April 2007, 07:49
The great thing about math is that no established result can ever be overturned (unlike in any other science, where all established results to date are subject to be replaced by a better, more coherent theory), since a mathematical result cannot be 'established' until proven rigorously. For example, the Goldbach Conjecture is almost guaranteed to be true, and many famous mathematicians such as Leonhard Euler have agreed to that sentiment, yet it is still an open problem with no end in sight because no one is able to prove it rigorously.
Philosophy can dissaprove anything.
dan_the_man
2nd April 2007, 10:38
Philosophy can dissaprove anything.
And that is why I wish to study it.:woot:
Juice
2nd April 2007, 12:42
Philosophy can dissaprove anything.
Not really. Have you ever taken a philosophy course?
JB
Maples
4th April 2007, 02:25
I got the chance to take Philosophy at A-level (not sure of Canadian equivalent: sixth form/college exams). Really interesting subject and well worth a go if you like that kind of thing!
dan_the_man
4th April 2007, 04:21
Hmm, the conversation seems to have gone from mathematical to philosophical now...still interesting, though. ;)
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